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tangent f(x)=sqrt(8x-10),(4,sqrt(22))

解答

切线

f (x) = 8 x - 10, (4, 22)

解答

y = \frac{2 2}{11} x + 22 - \frac{8 2}{11}

求解步骤

计算

f (x) = 8 x - 10

的斜率:

\frac{df ( x )}{d x} = \frac{4}{8 x - 10}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2 2}{11}

找到斜率 m=

\frac{2 2}{11}

且穿过

(4, 22)

的直线:

y = \frac{2 2}{11} x + 22 - \frac{8 2}{11}

y = \frac{2 2}{11} x + 22 - \frac{8 2}{11}

作图

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