f^'(x)=ln(x)

Lösung

f^{^{'}} (x) = ln (x)

f (x) = x ln (x) - x + c_{1}

Schritte zur Lösung

f^{'} (x) = ln (x)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int ln (x) d x

\int ln (x) d x = x ln (x) - x + c_{1}

f (x) = x ln (x) - x + c_{1}

\int \frac{1}{x x ^{2} - 36} d x

\frac{\partial}{\partial y} (y - \frac{y}{x ^{2} + y ^{2}})

\frac{d N}{d x} = ((0.0922) N) (1 - \frac{N}{60})

\frac{d}{d x} ((e^{x} - e^{- 2 x})^{\frac{1}{5}})

\frac{d}{d x} (\frac{( 3 x - 1 )}{2 x + 1})