y^'=x+3y

Lösung

y^{^{'}} = x + 3 y

y = - \frac{3 x + 1}{9} + c_{1} e^{3 x}

Schritte zur Lösung

y^{'} (x) = x + 3 y

Solve linear ODE:

y = - \frac{3 x + 1}{9} + c_{1} e^{3 x}

y = - \frac{3 x + 1}{9} + c_{1} e^{3 x}

d er i v a t i v e (1 - 2 x)^{\frac{1}{2}}

\int (\frac{1 + cos ( 2 x )}{2})^{2} d x

d er i v a t i v e cos (ln (t))

x \frac{d y}{d x} + 4 y = x^{- 3} e^{x}

\int \frac{x}{2} d x