integral from 1 to 16 of 1/(sqrt(x))

Lösung

\int_{1}^{16} \frac{1}{x} d x

6

Schritte zur Lösung

\int_{1}^{16} \frac{1}{x} d x

Wende die Potenzregel an

= [2 x^{\frac{1}{2}}]_{1}^{16}

Wende Radikal Regel an:

a^{\frac{1}{n}} = n a

= [2 x]_{1}^{16}

Berechne die Grenzen:

6

= 6

\int \frac{2 x}{3 ( x ^{2} + 1 )} d x

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\frac{d}{d x} ((x sin (2 x))^{\frac{3}{2}})

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\frac{\partial}{\partial α} (K (α) (α)^{α} L^{1 - α})