derivative x=6.4sin(1.2^2t^2)

Lösung

ableitung von

x = 6.4 sin (1. 2^{2} t^{2})

18.432 t cos (1.44 t^{2})

Schritte zur Lösung

\frac{d}{d t} (6.4 sin (1. 2^{2} t^{2}))

Vereinfache

6.4 sin (1. 2^{2} t^{2}) : 6.4 sin (1.44 t^{2})

= \frac{d}{d t} (6.4 sin (1.44 t^{2}))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 6.4 \frac{d}{d t} (sin (1.44 t^{2}))

Wende die Kettenregel an:

cos (1.44 t^{2}) \frac{d}{d t} (1.44 t^{2})

= cos (1.44 t^{2}) \frac{d}{d t} (1.44 t^{2})

\frac{d}{d t} (1.44 t^{2}) = 2.88 t

= 6.4 cos (1.44 t^{2}) \cdot 2.88 t

Vereinfache

= 18.432 t cos (1.44 t^{2})

\frac{\partial ^{2}}{\partial x \partial y} (x^{5} + x^{2} y + x + 3)

d er i v a t i v e - 7

\int cos (30 x) \cdot cos (4 x) \cdot cos (4 x) d x

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\frac{\partial}{\partial v} (u (v, w) + v e^{w})