(\partial ^2)/(\partial x^2)(ln(2+x^2y^2))

Lösung

\frac{\partial ^{2}}{\partial x ^{2}} (ln (2 + x^{2} y^{2}))

\frac{2 y ^{2} ( 2 - x ^{2} y ^{2} )}{( 2 + x ^{2} y ^{2} ) ^{2}}

Schritte zur Lösung

\frac{\partial ^{2}}{\partial x ^{2}} (ln (2 + x^{2} y^{2}))

\frac{\partial}{\partial x} (ln (2 + x^{2} y^{2})) = \frac{2 x y ^{2}}{2 + x ^{2} y ^{2}}

= \frac{\partial}{\partial x} (\frac{2 x y ^{2}}{2 + x ^{2} y ^{2}})

\frac{\partial}{\partial x} (\frac{2 x y ^{2}}{2 + x ^{2} y ^{2}}) = \frac{2 y ^{2} ( 2 - x ^{2} y ^{2} )}{( 2 + x ^{2} y ^{2} ) ^{2}}

= \frac{2 y ^{2} ( 2 - x ^{2} y ^{2} )}{( 2 + x ^{2} y ^{2} ) ^{2}}

\int tan^{3} (2 x) d x

t an g e n t y = f (x), at x = 7

l a pl a ce t r an s f or m 8 t

a re a x^{2} - 6 x, - x^{2} + 4 x

\int \frac{2 x ^{2} + x + 1}{x ^{3} + 2 x ^{2} + x} d x