What is the integral from-infinity to 0 of 1/(5-3x) ?

The integral from-infinity to 0 of 1/(5-3x) is diverges

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integral from-infinity to 0 of 1/(5-3x)

\int_{- \infty}^{0} \frac{1}{5 - 3 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{5 - 3 x} d x

Compute the indefinite integral:

\int \frac{1}{5 - 3 x} d x = - \frac{1}{3} ln ∣ 5 - 3 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{5 - 3 x} d x =

diverges

= diverges

y^{^{'}} + y tan (t) = \frac{tan ( t )}{cos ( t )}

\int x^{3} I n (x) d x

e^{t} + 3, at t = 0

y^{^{''}} + 4 y = sin (t)

x^{- 2}, 6

What is the integral from-infinity to 0 of 1/(5-3x) ?
The integral from-infinity to 0 of 1/(5-3x) is diverges