y^{''}+25y=3sec^3(5)

解答

y^{^{''}} + 25 y = 3 sec^{3} (5)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{3 sec ^{3} ( 5 )}{25}

求解步骤

y^{''} (t) + 25 y = 3 sec^{3} (5)

求解线性方程:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{3 sec ^{3} ( 5 )}{25}

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{3 sec ^{3} ( 5 )}{25}

s im pl i f y \frac{x}{x ^{2} + y ^{2}}

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