integral from-1 to 1 of-2y^2+2

Lösung

\int_{- 1}^{1} - 2 y^{2} + 2 d y

\frac{8}{3}

Dezimale

2.66666 \dots

Schritte zur Lösung

\int_{- 1}^{1} - 2 y^{2} + 2 d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{1} 2 y^{2} d y + \int_{- 1}^{1} 2 d y

\int_{- 1}^{1} 2 y^{2} d y = \frac{4}{3}

\int_{- 1}^{1} 2 d y = 4

= - \frac{4}{3} + 4

Vereinfache

- \frac{4}{3} + 4 : \frac{8}{3}

= \frac{8}{3}

y^{^{''}} + 18 y^{^{'}} + 80 y = 0

\int_{0}^{1} \frac{25}{x ^{5}} d x

\int_{- 3}^{0} \frac{9}{9 x + 4} d x

\int \frac{20}{1 + x ^{2}} d x

n = 1 \sum \infty \frac{1}{ln ( n )}