What is the solution for 9y^{''}+18y^'+17y=0 ?

The solution for 9y^{''}+18y^'+17y=0 is y=e^{-t}(c_{1}cos((2^{3/2}t)/3)+c_{2}sin((2^{3/2}t)/3))

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9y^{''}+18y^'+17y=0

9 y^{^{''}} + 18 y^{^{'}} + 17 y = 0

y = e^{- t} (c_{1} cos (\frac{2 ^{\frac{3}{2}} t}{3}) + c_{2} sin (\frac{2 ^{\frac{3}{2}} t}{3}))

Solution steps

9 y^{''} (t) + 18 y^{'} (t) + 17 y = 0

Solve linear ODE:

y = e^{- t} (c_{1} cos (\frac{2 ^{\frac{3}{2}} t}{3}) + c_{2} sin (\frac{2 ^{\frac{3}{2}} t}{3}))

y = e^{- t} (c_{1} cos (\frac{2 ^{\frac{3}{2}} t}{3}) + c_{2} sin (\frac{2 ^{\frac{3}{2}} t}{3}))

n = 1 \sum \infty \frac{2 n}{5 n + 1}

\frac{\partial}{\partial y} (\frac{12 x}{x + y})

\frac{d y}{d x} = y - 2

sin (3 x + 1)

x \to - 7 lim (- 13)

What is the solution for 9y^{''}+18y^'+17y=0 ?
The solution for 9y^{''}+18y^'+17y=0 is y=e^{-t}(c_{1}cos((2^{3/2}t)/3)+c_{2}sin((2^{3/2}t)/3))