zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的微积分 >

tangent f(x)=(x-1)^2+1,\at x=-1

解答

切线

f (x) = (x - 1)^{2} + 1, at x = - 1

解答

y = - 4 x + 1

求解步骤

找到切点:

(- 1, 5)

计算

f (x) = (x - 1)^{2} + 1

的斜率:

\frac{df ( x )}{d x} = 2 x - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

找到斜率 m=

- 4

且穿过

(- 1, 5)

的直线:

y = - 4 x + 1

y = - 4 x + 1

作图

流行的例子

面积 f(x)=-10x+5,(1,2)

a re a f (x) = - 10 x + 5, (1, 2)

integral of x^2sqrt(4x^2+1)

\int x^{2} 4 x^{2} + 1 d x

limit as x approaches 3 of (x^2)/x

x \to 3 lim (\frac{x ^{2}}{x})

derivative of (sin(3x+1)/(7x^2+1))

\frac{d}{d x} (\frac{sin ( 3 x + 1 )}{7 x ^{2} + 1})

integral of (12x)/(sqrt(1-x^4))

\int \frac{12 x}{1 - x ^{4}} d x