(\partial)/(\partial x)(-2xy+x^3)

解答

\frac{\partial}{\partial x} (- 2 x y + x^{3})

- 2 y + 3 x^{2}

求解步骤

\frac{\partial}{\partial x} (- 2 x y + x^{3})

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (x^{3})

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

= - 2 y + 3 x^{2}

t an g e n t f (x) = 2 - 3 x^{2}, at x = - 2

\frac{d y}{d x} = y^{2} - 2 y

\frac{d}{d x} (e^{2 x} \cdot sin (x^{2} + 5))

t an g e n t 2 x^{3} - x^{2} + 3

\frac{d}{d y} (ln (x^{2} + y^{2}))