derivative f(x)=-3x^2+24x-36

Lösung

ableitung von

f (x) = - 3 x^{2} + 24 x - 36

- 6 x + 24

Schritte zur Lösung

\frac{d}{d x} (- 3 x^{2} + 24 x - 36)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (24 x) - \frac{d}{d x} (36)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (24 x) = 24

\frac{d}{d x} (36) = 0

= - 6 x + 24 - 0

Vereinfache

= - 6 x + 24

\int \frac{5 - 50 x}{36 - 25 x ^{2}} d x

\frac{\partial}{\partial x} (\frac{5 x yz}{x ^{2} + y ^{2} + z ^{2}})

y^{^{'}} + 2 y = 10 sin (t)

d er i v a t i v e e^{t} \cdot sin (2 t)

x \to 1 lim (\frac{x ^{2 n} - 2 x ^{n} + 1}{x ^{2 m} - 2 x ^{m} + 1})