y^'=-sqrt(x)

Lösung

y^{^{'}} = - x

y = - \frac{2}{3} x^{\frac{3}{2}} + c_{1}

Schritte zur Lösung

y^{'} (x) = - x

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int - x d x

\int - x d x = - \frac{2}{3} x^{\frac{3}{2}} + c_{1}

y = - \frac{2}{3} x^{\frac{3}{2}} + c_{1}

d er i v a t i v e y = (\frac{x ^{2} + 6}{x ^{2} - 6})^{3}

\frac{d}{d x} (arcsin (3 x) + arccos (3 x))

\frac{d}{d x} (arccot (\frac{x}{8}))

x \to 0 lim ((1 + x)^{\frac{3}{x}})

y^{^{''}} - \frac{5}{t} y^{^{'}} + \frac{18}{t ^{2}} y = 0