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Beliebt Rechnen >

limit as x approaches 0 of 1/(ln(1+x))-1/x

Lösung

x \to 0 lim (\frac{1}{ln ( 1 + x )} - \frac{1}{x})

Lösung

\frac{1}{2}

+1

Dezimale

0.5

Schritte zur Lösung

x \to 0 lim (\frac{1}{ln ( 1 + x )} - \frac{1}{x})

Vereinfache

\frac{1}{ln ( 1 + x )} - \frac{1}{x} : \frac{x - ln ( x + 1 )}{x ln ( x + 1 )}

= x \to 0 lim (\frac{x - ln ( x + 1 )}{x ln ( x + 1 )})

Wende das L'Hopital Theorem an

= x \to 0 lim (\frac{1 - \frac{1}{x + 1}}{ln ( x + 1 ) + \frac{x}{x + 1}})

Wende das L'Hopital Theorem an

= x \to 0 lim (\frac{\frac{1}{( x + 1 ) ^{2}}}{\frac{x + 2}{( x + 1 ) ^{2}}})

Setze den Wert

x = 0

ein

= \frac{\frac{1}{( 0 + 1 ) ^{2}}}{\frac{0 + 2}{( 0 + 1 ) ^{2}}}

Vereinfache

\frac{\frac{1}{( 0 + 1 ) ^{2}}}{\frac{0 + 2}{( 0 + 1 ) ^{2}}} : \frac{1}{2}

= \frac{1}{2}

Graph

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