(\partial)/(\partial x)(1/(xy^2-x^2y))

解答

\frac{\partial}{\partial x} (\frac{1}{x y ^{2} - x ^{2} y})

- \frac{y - 2 x}{x ^{2} y ( y - x ) ^{2}}

求解步骤

\frac{\partial}{\partial x} (\frac{1}{x y ^{2} - x ^{2} y})

将

y

视为常数

使用指数法则:

\frac{1}{a} = a^{- 1}

= \frac{\partial}{\partial x} ((x y^{2} - x^{2} y)^{- 1})

使用连锁律:

- \frac{1}{( x y ^{2} - x ^{2} y ) ^{2}} \frac{\partial}{\partial x} (x y^{2} - x^{2} y)

= - \frac{1}{( x y ^{2} - x ^{2} y ) ^{2}} \frac{\partial}{\partial x} (x y^{2} - x^{2} y)

\frac{\partial}{\partial x} (x y^{2} - x^{2} y) = y^{2} - 2 y x

= - \frac{1}{( x y ^{2} - x ^{2} y ) ^{2}} (y^{2} - 2 y x)

化简

- \frac{1}{( x y ^{2} - x ^{2} y ) ^{2}} (y^{2} - 2 y x) : - \frac{y - 2 x}{x ^{2} y ( y - x ) ^{2}}

= - \frac{y - 2 x}{x ^{2} y ( y - x ) ^{2}}

x \to 0 lim ((e^{x} + x)^{\frac{1}{x}})

(x + 1) \frac{d y}{d x} + y = x ln^{2} (x)

x \to \infty lim (\frac{( ln ( e ^{3 x} + x ) )}{x})

t \frac{d y}{d t} + 2 y = t^{4}

\frac{\partial}{\partial y} (x ln (y) - y ln (x))