(\partial)/(\partial z)(5sin^2(z))

解答

\frac{\partial}{\partial z} (5 sin^{2} (z))

5 sin (2 z)

求解步骤

\frac{\partial}{\partial z} (5 sin^{2} (z))

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{\partial}{\partial z} (sin^{2} (z))

使用连锁律:

2 sin (z) \frac{\partial}{\partial z} (sin (z))

= 2 sin (z) \frac{\partial}{\partial z} (sin (z))

\frac{\partial}{\partial z} (sin (z)) = cos (z)

= 5 \cdot 2 sin (z) cos (z)

化简

5 \cdot 2 sin (z) cos (z) : 5 sin (2 z)

= 5 sin (2 z)

n = 1 \sum \infty 4 + (- 1)^{n}

\int 5 (tan (x)) (ln (cos (x))) d x

\int_{2}^{\infty} \frac{1}{3 x + 2} d x

d er i v a t i v e 5 x + 1

\int e^{x} sin (6 e^{x} + 3) d x