faktorisieren 2(x+1)^2+x+1

Lösung

faktorisieren

2 (x + 1)^{2} + x + 1

(x + 1) (2 x + 3)

Schritte zur Lösung

2 (x + 1)^{2} + x + 1

Klammere gleiche Terme aus

(x + 1) : (x + 1) (2 (x + 1) + 1)

= (x + 1) (2 (x + 1) + 1)

Schreibe

2 (x + 1) + 1

um:

2 x + 3

= (x + 1) (2 x + 3)

2 x + 1 = 4

x^{2} - 5 \leq 2 x + 3

7 \leq ∣ x ∣ \leq 9

f a c t or 2 π r^{2} + 2 π

x^{2} - 20 x = 0