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人気のある代数 >

solvefor x,(3x+2)(5x-7)=fx^2+gx+hg

解

解く

x, (3 x + 2) (5 x - 7) = f x^{2} + gx + h g

解

x = \frac{11 + g + g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}, x = \frac{11 + g - g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}; f \neq = 15

解答ステップ

(3 x + 2) (5 x - 7) = f x^{2} + gx + h g

拡張

(3 x + 2) (5 x - 7) : 15 x^{2} - 11 x - 14

15 x^{2} - 11 x - 14 = f x^{2} + gx + h g

h g

を左側に移動します

15 x^{2} - 11 x - 14 - h g = f x^{2} + gx

gx

を左側に移動します

15 x^{2} - 11 x - 14 - h g - gx = f x^{2}

f x^{2}

を左側に移動します

15 x^{2} - 11 x - 14 - h g - gx - f x^{2} = 0

標準的な形式で書く

a x^{2} + b x + c = 0

(15 - f) x^{2} - (11 + g) x - 14 - h g = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 11 - g ) \pm ( - 11 - g ) ^{2} - 4 ( 15 - f ) ( - 14 - h g )}{2 ( 15 - f )}

簡素化

(- 11 - g)^{2} - 4 (15 - f) (- 14 - h g) : g^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f

x_{1, 2} = \frac{- ( - 11 - g ) \pm g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}; f \neq = 15

解を分離する

x_{1} = \frac{- ( - 11 - g ) + g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}, x_{2} = \frac{- ( - 11 - g ) - g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}

x = \frac{- ( - 11 - g ) + g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )} : \frac{11 + g + g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}

x = \frac{- ( - 11 - g ) - g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )} : \frac{11 + g - g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}

二次equationの解:

x = \frac{11 + g + g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}, x = \frac{11 + g - g ^{2} + 22 g + 60 h g - 4 h f g + 961 - 56 f}{2 ( 15 - f )}; f \neq = 15

グラフ

人気の例

因数 x^2-7x-8

f a c t or x^{2} - 7 x - 8

2 + 3 x \leq 3 x - 7

s im pl i f y ∣ - 5 + 9 ∣

- 120 = - 8 x

(x-1)^2+(0-4)^2=36

(x - 1)^{2} + (0 - 4)^{2} = 36