w^2+7w+12=0

解

w^{2} + 7 w + 12 = 0

w = - 3, w = - 4

解答ステップ

w^{2} + 7 w + 12 = 0

解くとthe二次式

w_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

w_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

解を分離する

w_{1} = \frac{- 7 + 1}{2 \cdot 1}, w_{2} = \frac{- 7 - 1}{2 \cdot 1}

w = \frac{- 7 + 1}{2 \cdot 1} : - 3

w = \frac{- 7 - 1}{2 \cdot 1} : - 4

二次equationの解:

w = - 3, w = - 4