What are the solutions to the equation x^2=13+6x ?

The solutions to the equation x^2=13+6x are x=3+sqrt(22),x=3-sqrt(22)

Find the zeros of x^2=13+6x

The zeros of x^2=13+6x are x=3+sqrt(22),x=3-sqrt(22)

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x^{2} = 13 + 6 x

x = 3 + 22, x = 3 - 22

Decimal Notation

x = 7.69041 \dots, x = - 1.69041 \dots

Solution steps

x^{2} = 13 + 6 x

Move

6 x

to the left side

x^{2} - 6 x = 13

Move

13

to the left side

x^{2} - 6 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 13) = 222

x_{1, 2} = \frac{- ( - 6 ) \pm 2 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 22}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 22}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 22}{2 \cdot 1} : 3 + 22

x = \frac{- ( - 6 ) - 2 22}{2 \cdot 1} : 3 - 22

The solutions to the quadratic equation are:

x = 3 + 22, x = 3 - 22

{6 + [9 - (- 5 + 10) + (7 - 3)] + [(- 3) - (- 12) + 13]}

\frac{1}{2 + \frac{1}{1 + \frac{1}{2}}}

8 = 14 n

- (7)^{- 2}

2 x^{2} + 3 x - 2 > 0

What are the solutions to the equation x^2=13+6x ?
The solutions to the equation x^2=13+6x are x=3+sqrt(22),x=3-sqrt(22)
Find the zeros of x^2=13+6x
The zeros of x^2=13+6x are x=3+sqrt(22),x=3-sqrt(22)