|(2x-8)/4 |>9

Lösung

\frac{2 x - 8}{4} > 9

x < - 14 or x > 22

Intervall-Notation

(- \infty, - 14) \cup (22, \infty)

Schritte zur Lösung

\frac{2 x - 8}{4} > 9

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

\frac{2 x - 8}{4} < - 9 or \frac{2 x - 8}{4} > 9

\frac{2 x - 8}{4} < - 9 or \frac{2 x - 8}{4} > 9

x < - 14 or x > 22

\frac{n}{2} - 1 \geq 1

8 n^{2} + n - 3 = - 3 n

6 (x - 3) + 5 (x + 4) = 15

10 - (\frac{( x - 15 )}{3})^{2} 9 < x \leq 24

- 2 a - 4 = - 8