解答
1003x2+(1003+21001)x+199=0
解答
x=2006−1003−21001+100310060091010013+100341001−796,x=2006−1003−21001−100310060091010013+100341001−796
+1
十进制
x=−0.24148…,x=−0.82160…求解步骤
1003x2+(1003+21001)x+199=0
两边除以 100310031003x2+1003(1003+21001)x+1003199=10030
改写成标准形式 ax2+bx+c=0x2+(1+100321001)x+1003199=0
使用求根公式求解
x1,2=2⋅1−(1+100321001)±(1+100321001)2−4⋅1⋅1003199
(1+100321001)2−4⋅1⋅1003199=10060091010013+100341001−796
x1,2=2⋅1−(1+100321001)±10060091010013+100341001−796
将解分隔开x1=2⋅1−(1+100321001)+10060091010013+100341001−796,x2=2⋅1−(1+100321001)−10060091010013+100341001−796
x=2⋅1−(1+100321001)+10060091010013+100341001−796:2006−1003−21001+100310060091010013+100341001−796
x=2⋅1−(1+100321001)−10060091010013+100341001−796:2006−1003−21001−100310060091010013+100341001−796
二次方程组的解是:x=2006−1003−21001+100310060091010013+100341001−796,x=2006−1003−21001−100310060091010013+100341001−796