de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

faktorisieren 4x^2(x-3)^3-6x(x-3)^2+4(x-3)

Lösung

faktorisieren

4 x^{2} (x - 3)^{3} - 6 x (x - 3)^{2} + 4 (x - 3)

Lösung

2 (x - 3) (2 x^{4} - 12 x^{3} + 15 x^{2} + 9 x + 2)

Schritte zur Lösung

4 x^{2} (x - 3)^{3} - 6 x (x - 3)^{2} + 4 (x - 3)

Klammere gleiche Terme aus

2 (x - 3) : 2 (x - 3) (2 x^{2} (x - 3)^{2} - 3 x (x - 3) + 2)

= 2 (x - 3) (2 x^{2} (x - 3)^{2} - 3 x (x - 3) + 2)

Schreibe

2 x^{2} (x - 3)^{2} - 3 x (x - 3) + 2

um:

2 x^{4} - 12 x^{3} + 15 x^{2} + 9 x + 2

= 2 (x - 3) (2 x^{4} - 12 x^{3} + 15 x^{2} + 9 x + 2)

Beliebte Beispiele

faktorisieren-x^2-8x+20

f a c t or - x^{2} - 8 x + 20

r^{2} + 4 r + 5 = 0

4 x^{2} + 12 x = 8 x - 4

4 x^{2} - 12 x - 27 = 0

1/(16pi)((8+2pi)x-124pi)=0

\frac{1}{16 π} ((8 + 2 π) x - 124 π) = 0