2x^2+14x+12=0

解

2 x^{2} + 14 x + 12 = 0

x = - 1, x = - 6

解答ステップ

2 x^{2} + 14 x + 12 = 0

解くとthe二次式

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

1 4^{2} - 4 \cdot 2 \cdot 12 = 10

x_{1, 2} = \frac{- 14 \pm 10}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 14 + 10}{2 \cdot 2}, x_{2} = \frac{- 14 - 10}{2 \cdot 2}

x = \frac{- 14 + 10}{2 \cdot 2} : - 1

x = \frac{- 14 - 10}{2 \cdot 2} : - 6

二次equationの解:

x = - 1, x = - 6