|a-6|=3

Lösung

∣ a - 6 ∣ = 3

a = 3 or a = 9

Schritte zur Lösung

∣ a - 6 ∣ = 3

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

a - 6 = - 3 or a - 6 = 3

a - 6 = - 3 or a - 6 = 3

a = 3 or a = 9

2 (4 x - 3) \leq 5 x - 27

f a c t or 12 y^{3} + 26 y^{2} + 10 y

∣ x + 1 ∣ - ∣ x - 2 ∣ \geq 2

5 y^{2} - 3 y - 5 = 0

\frac{x + 2}{x + 3} < \frac{x - 1}{x - 2}