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Popular >

7-|2x+9|<= 2

Solution

7 - ∣ 2 x + 9 ∣ \leq 2

Solution

x \leq - 7 or x \geq - 2

+1

Interval Notation

(- \infty, - 7] \cup [- 2, \infty)

Solution steps

7 - ∣ 2 x + 9 ∣ \leq 2

Move

7

to the right side

- ∣ 2 x + 9 ∣ \leq - 5

Multiply both sides by

- 1

∣ 2 x + 9 ∣ \geq 5

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

2 x + 9 \leq - 5 or 2 x + 9 \geq 5

2 x + 9 \leq - 5 or 2 x + 9 \geq 5

x \leq - 7 or x \geq - 2

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7 (x - 4)^{2} - 3 (x + 5)^{2} = 4 (x + 1) - 2

simplify sqrt(41)simplify

41

\frac{7 x}{3} + 2 = \frac{1}{3}

a - 4 = 16 - a^{2}

factor x^3+6x^2-4x-24 factor

x^{3} + 6 x^{2} - 4 x - 24

Frequently Asked Questions (FAQ)

What is 7-|2x+9|<= 2 ?
The solution to 7-|2x+9|<= 2 is x<=-7\lor x>=-2