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Beliebt Algebra >

(x-2)/(x-1)<= (x+2)/(x+1)

Lösung

\frac{x - 2}{x - 1} \leq \frac{x + 2}{x + 1}

Lösung

- 1 < x \leq 0 or x > 1

+1

Intervall-Notation

(- 1, 0] \cup (1, \infty)

Schritte zur Lösung

\frac{x - 2}{x - 1} \leq \frac{x + 2}{x + 1}

Rewrite in standard form

\frac{x}{( x - 1 ) ( x + 1 )} \geq 0

Identifiziere die Intervalle

- 1 < x \leq 0 or x > 1

Graph

Beliebte Beispiele

(x-5)(x-2)^2(x-7)>= 0

(x - 5) (x - 2)^{2} (x - 7) \geq 0

2 x - \frac{1}{2} = x + \frac{7}{2}

- 5 (4 x - 5) = 5 x

-x^2+x+20= 3/4 x^2-x

- x^{2} + x + 20 = \frac{3}{4} x^{2} - x

faktorisieren 10x^3-8x^2+25x-20

f a c t or 10 x^{3} - 8 x^{2} + 25 x - 20