|x^2-3x|=2

解

x^{2} - 3 x = 2

x = \frac{3 - 17}{2} or x = 1 or x = 2 or x = \frac{3 + 17}{2}

十進法表記

x = - 0.56155 \dots, x = 1, x = 2, x = 3.56155 \dots

解答ステップ

x^{2} - 3 x = 2

絶対規則を適用する:

∣ u ∣ = a, a > 0

の場合は

u = a

u = - a

x^{2} - 3 x = - 2 or x^{2} - 3 x = 2

x^{2} - 3 x = - 2 or x^{2} - 3 x = 2

(x = 1 or x = 2) or (x = \frac{3 - 17}{2} or x = \frac{3 + 17}{2})

x = \frac{3 - 17}{2} or x = 1 or x = 2 or x = \frac{3 + 17}{2}