What are the solutions to the equation 3(x-4)(x+5)=0 ?

The solutions to the equation 3(x-4)(x+5)=0 are x=4,x=-5

Find the zeros of 3(x-4)(x+5)=0

The zeros of 3(x-4)(x+5)=0 are x=4,x=-5

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3 (x - 4) (x + 5) = 0

x = 4, x = - 5

Solution steps

3 (x - 4) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 5 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

x (55 - x) = 750

a^{2} + 2 a

(3 - 5 i)^{2}

\frac{( 2 x ^{3} z ^{2} ) ^{3}}{x ^{3} y ^{4} z ^{2} \cdot x ^{- 4} z ^{3}}

- 9 m - 27

What are the solutions to the equation 3(x-4)(x+5)=0 ?
The solutions to the equation 3(x-4)(x+5)=0 are x=4,x=-5
Find the zeros of 3(x-4)(x+5)=0
The zeros of 3(x-4)(x+5)=0 are x=4,x=-5