化简 i/(3-2i)

解答

化简

\frac{i}{3 - 2 i}

- \frac{2}{13} + \frac{3}{13} i

求解步骤

\frac{i}{3 - 2 i}

乘以共轭根式

\frac{3 + 2 i}{3 + 2 i}

= \frac{i ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )}

化简

\frac{i ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )} : \frac{3 i - 2}{13}

= \frac{3 i - 2}{13}

Rewrite in standard complex form:

- \frac{2}{13} + \frac{3}{13} i

= - \frac{2}{13} + \frac{3}{13} i

- 5 x^{2} + 10 x + 15 = 0

\frac{3}{4} x - \frac{1}{2} \leq \frac{1}{8}

f a c t or a^{2} + 7 ab - 18 b^{2}

(x + 4) (7 - x) (x - 5) \geq 0

n - (- 2) = - 14