faktorisieren 32c^5-d^5

Lösung

faktorisieren

32 c^{5} - d^{5}

(2 c - d) (16 c^{4} + 8 c^{3} d + 4 c^{2} d^{2} + 2 c d^{3} + d^{4})

Schritte zur Lösung

32 c^{5} - d^{5}

Wende Exponentenregel an

= (2 c)^{5} - d^{5}

Apply factoring rule:

x^{n} + y^{n} = (x + y) (x^{n - 1} - x^{n - 2} y + \dots - x y^{n - 2} + y^{n - 1}), n i s o dd

(2 c)^{5} - d^{5} = (2 c - d) (2^{4} c^{4} + 2^{3} c^{3} d + 2^{2} c^{2} d^{2} + 2 c d^{3} + d^{4})

= (2 c - d) (2^{4} c^{4} + 2^{3} c^{3} d + 2^{2} c^{2} d^{2} + 2 c d^{3} + d^{4})

Vereinfache

(2 c - d) (2^{4} c^{4} + 2^{3} c^{3} d + 2^{2} c^{2} d^{2} + 2 c d^{3} + d^{4}) : (2 c - d) (16 c^{4} + 8 c^{3} d + 4 c^{2} d^{2} + 2 c d^{3} + d^{4})

= (2 c - d) (16 c^{4} + 8 c^{3} d + 4 c^{2} d^{2} + 2 c d^{3} + d^{4})

x^{2} + 18 x = - 32

f a c t or 63 - 28 y^{2}

s im pl i f y (\frac{9}{16})^{6}

(x + 4)^{2} = - 25

∣ 8 x + 3 ∣ + 6 < 8