因式分解 1-64b^3

解答

因式分解

1 - 64 b^{3}

- (4 b - 1) (16 b^{2} + 4 b + 1)

求解步骤

1 - 64 b^{3}

改写成标准形式

= - 64 b^{3} + 1

因式分解

- 1 : - (64 b^{3} - 1)

= - (64 b^{3} - 1)

因式分解

64 b^{3} - 1 : (4 b - 1) (4^{2} b^{2} + 4 b + 1)

= - (4 b - 1) (4^{2} b^{2} + 4 b + 1)

4^{2} = 16

= - (4 b - 1) (16 b^{2} + 4 b + 1)

2 \geq \frac{8 + x}{11}

5 (11 x - 18) = 3 (2 x + 7)

f a c t or - 7 x^{2} - 11 x - 4

f a c t or 15 x^{4} - 27 x^{3} y - 6 x^{2} y^{2}

f a c t or 5 + 7 x^{4} - 6 x^{8}