What are the solutions to the equation x^2-12x-1=0 ?

The solutions to the equation x^2-12x-1=0 are x=6+sqrt(37),x=6-sqrt(37)

Find the zeros of x^2-12x-1=0

The zeros of x^2-12x-1=0 are x=6+sqrt(37),x=6-sqrt(37)

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x^{2} - 12 x - 1 = 0

x = 6 + 37, x = 6 - 37

Decimal Notation

x = 12.08276 \dots, x = - 0.08276 \dots

Solution steps

x^{2} - 12 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 1) = 237

x_{1, 2} = \frac{- ( - 12 ) \pm 2 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 37}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 37}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 37}{2 \cdot 1} : 6 + 37

x = \frac{- ( - 12 ) - 2 37}{2 \cdot 1} : 6 - 37

The solutions to the quadratic equation are:

x = 6 + 37, x = 6 - 37

0 = x^{2} + 2 x

- 44 > - 2 x - 8 \geq - 8

9 e + 4 = 5 e + 14 + 13 e

x + 4 = 13

(\frac{3}{5}) (- \frac{6}{7}) (- 4)

What are the solutions to the equation x^2-12x-1=0 ?
The solutions to the equation x^2-12x-1=0 are x=6+sqrt(37),x=6-sqrt(37)
Find the zeros of x^2-12x-1=0
The zeros of x^2-12x-1=0 are x=6+sqrt(37),x=6-sqrt(37)