(12)/(x-6)+6/(2x-1)>=-1

Lösung

\frac{12}{x - 6} + \frac{6}{2 x - 1} \geq - 1

x \leq - \frac{21}{2} or \frac{1}{2} < x \leq 2 or x > 6

Intervall-Notation

(- \infty, - \frac{21}{2}] \cup (\frac{1}{2}, 2] \cup (6, \infty)

Dezimale

x \leq - 10.5 or 0.5 < x \leq 2 or x > 6

Schritte zur Lösung

\frac{12}{x - 6} + \frac{6}{2 x - 1} \geq - 1

Rewrite in standard form

\frac{2 x ^{2} + 17 x - 42}{( x - 6 ) ( 2 x - 1 )} \geq 0

Faktorisiere

\frac{2 x ^{2} + 17 x - 42}{( x - 6 ) ( 2 x - 1 )} : \frac{( x - 2 ) ( 2 x + 21 )}{( x - 6 ) ( 2 x - 1 )}

\frac{( x - 2 ) ( 2 x + 21 )}{( x - 6 ) ( 2 x - 1 )} \geq 0

Identifiziere die Intervalle

x \leq - \frac{21}{2} or \frac{1}{2} < x \leq 2 or x > 6

4 ∣ x + 4 ∣ + 6 < 30

4 u - 2 = 14

f a c t or x^{2} + 2 x y - 24 y^{2}

s im pl i f y \frac{40 x ^{8} y ^{8}}{8 x ^{7} y}

3 (2 x + 5) = 39