What are the solutions to the equation 4x^2=11x+45 ?

The solutions to the equation 4x^2=11x+45 are x=5,x=-9/4

Find the zeros of 4x^2=11x+45

The zeros of 4x^2=11x+45 are x=5,x=-9/4

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4 x^{2} = 11 x + 45

x = 5, x = - \frac{9}{4}

Decimal Notation

x = 5, x = - 2.25

Solution steps

4 x^{2} = 11 x + 45

Move

45

to the left side

4 x^{2} - 45 = 11 x

Move

11 x

to the left side

4 x^{2} - 45 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 11 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 ( - 45 )}{2 \cdot 4}

(- 11)^{2} - 4 \cdot 4 (- 45) = 29

x_{1, 2} = \frac{- ( - 11 ) \pm 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 29}{2 \cdot 4}, x_{2} = \frac{- ( - 11 ) - 29}{2 \cdot 4}

x = \frac{- ( - 11 ) + 29}{2 \cdot 4} : 5

x = \frac{- ( - 11 ) - 29}{2 \cdot 4} : - \frac{9}{4}

The solutions to the quadratic equation are:

x = 5, x = - \frac{9}{4}

m - 5 = - 10

4 (4 + 2 m) = 48

4 + y = 7

5 x - 15

2 + \frac{v}{6} \geq 9

What are the solutions to the equation 4x^2=11x+45 ?
The solutions to the equation 4x^2=11x+45 are x=5,x=-9/4
Find the zeros of 4x^2=11x+45
The zeros of 4x^2=11x+45 are x=5,x=-9/4