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Frequently Asked Questions (FAQ)
What are the solutions to the equation -4x^2+16x=23 ?
- The solutions to the equation -4x^2+16x=23 are x=2-i(sqrt(7))/2 ,x=2+i(sqrt(7))/2
Find the zeros of -4x^2+16x=23
- The zeros of -4x^2+16x=23 are x=2-i(sqrt(7))/2 ,x=2+i(sqrt(7))/2