What are the solutions to the equation 3x^2+11x+5=0 ?

The solutions to the equation 3x^2+11x+5=0 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6

Find the zeros of 3x^2+11x+5=0

The zeros of 3x^2+11x+5=0 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6

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3 x^{2} + 11 x + 5 = 0

x = \frac{- 11 + 61}{6}, x = \frac{- 11 - 61}{6}

Decimal Notation

x = - 0.53162 \dots, x = - 3.13504 \dots

Solution steps

3 x^{2} + 11 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 5 = 61

x_{1, 2} = \frac{- 11 \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 61}{2 \cdot 3}, x_{2} = \frac{- 11 - 61}{2 \cdot 3}

x = \frac{- 11 + 61}{2 \cdot 3} : \frac{- 11 + 61}{6}

x = \frac{- 11 - 61}{2 \cdot 3} : \frac{- 11 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{- 11 + 61}{6}, x = \frac{- 11 - 61}{6}

52 + x^{2} = 13

y^{2} - 8 y + 25 = 0

F = 6 F

- 8 \leq - \frac{3}{2} z + 1 \leq - 2

∣ x - 5 ∣ \leq - 4

What are the solutions to the equation 3x^2+11x+5=0 ?
The solutions to the equation 3x^2+11x+5=0 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6
Find the zeros of 3x^2+11x+5=0
The zeros of 3x^2+11x+5=0 are x=(-11+sqrt(61))/6 ,x=(-11-sqrt(61))/6