de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

16x^3+16x^2>= x+1

Lösung

16 x^{3} + 16 x^{2} \geq x + 1

Lösung

- 1 \leq x \leq - \frac{1}{4} or x \geq \frac{1}{4}

+2

Intervall-Notation

[- 1, - \frac{1}{4}] \cup [\frac{1}{4}, \infty)

Dezimale

- 1 \leq x \leq - 0.25 or x \geq 0.25

Schritte zur Lösung

16 x^{3} + 16 x^{2} \geq x + 1

Rewrite in standard form

16 x^{3} + 16 x^{2} - 1 - x \geq 0

Faktorisiere

16 x^{3} + 16 x^{2} - 1 - x : (x + 1) (4 x + 1) (4 x - 1)

(x + 1) (4 x + 1) (4 x - 1) \geq 0

Identifiziere die Intervalle

- 1 \leq x \leq - \frac{1}{4} or x \geq \frac{1}{4}

Graph

Beliebte Beispiele

x^{2} + 2 x - 57 = x - 1

3 (x - 5) = x + 11

(- 2 - 2)^{3}

faktorisieren 35+30x

f a c t or 35 + 30 x

2 n + 6 = 18