-2x^2-4x+16=0

解

- 2 x^{2} - 4 x + 16 = 0

x = - 4, x = 2

解答ステップ

- 2 x^{2} - 4 x + 16 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 16}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 16 = 12

x_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 ( - 2 )}

解を分離する

x_{1} = \frac{- ( - 4 ) + 12}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 12}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 12}{2 ( - 2 )} : - 4

x = \frac{- ( - 4 ) - 12}{2 ( - 2 )} : 2

二次equationの解:

x = - 4, x = 2