What is the answer to solvefor x,log_{6}(x)+log_{6}(x)-5=2 ?

The answer to solvefor x,log_{6}(x)+log_{6}(x)-5=2 is x=216sqrt(6)

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Solve for x log base 6 of x+ log base 6 of x-5=2

solve for

x, lo g_{6} (x) + lo g_{6} (x) - 5 = 2

x = 2166

Decimal Notation

x = 529.08978 \dots

Solution steps

lo g_{6} (x) + lo g_{6} (x) - 5 = 2

Add similar elements:

lo g_{6} (x) + lo g_{6} (x) = 2 lo g_{6} (x)

2 lo g_{6} (x) - 5 = 2

Move

5

to the right side

2 lo g_{6} (x) = 7

Divide both sides by

2

lo g_{6} (x) = \frac{7}{2}

Apply log rules

x = 2166

Verify Solutions:

x = 2166

True

The solution is

x = 2166

lo g_{5} (2)

lo g_{36} (6) lo g_{6} (36)

lo g_{10} (16) - lo g_{10} (8)

x, lo g_{x} (8000) = 3

y, lo g_{4} (64) = y

What is the answer to solvefor x,log_{6}(x)+log_{6}(x)-5=2 ?
The answer to solvefor x,log_{6}(x)+log_{6}(x)-5=2 is x=216sqrt(6)