What is the answer to solvefor x,log_{2}(3x)-7=3 ?

The answer to solvefor x,log_{2}(3x)-7=3 is x= 1024/3

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Solve for x log base 2 of 3x-7=3

solve for

x, lo g_{2} (3 x) - 7 = 3

x = \frac{1024}{3}

Decimal Notation

x = 341.33333 \dots

Solution steps

lo g_{2} (3 x) - 7 = 3

Move

7

to the right side

lo g_{2} (3 x) = 10

Apply log rules

3 x = 1024

Solve

3 x = 1024 : x = \frac{1024}{3}

x = \frac{1024}{3}

Verify Solutions:

x = \frac{1024}{3}

True

The solution is

x = \frac{1024}{3}

x, lo g_{7} (49) = x

x, lo g_{2} (16) = x

\frac{lo g _{20} ( m )}{( n ^{5} p )}

\frac{22}{36}

- \frac{9}{16}

What is the answer to solvefor x,log_{2}(3x)-7=3 ?
The answer to solvefor x,log_{2}(3x)-7=3 is x= 1024/3