What are the solutions to the equation roots f(x)=x^3+2x^2-16x-32 ?

The solutions to the equation roots f(x)=x^3+2x^2-16x-32 are x=-2,x=-4,x=4

Find the zeros of roots f(x)=x^3+2x^2-16x-32

The zeros of roots f(x)=x^3+2x^2-16x-32 are x=-2,x=-4,x=4

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roots

f (x) = x^{3} + 2 x^{2} - 16 x - 32

x = - 2, x = - 4, x = 4

Solution steps

x^{3} + 2 x^{2} - 16 x - 32

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 2 x^{2} - 16 x - 32 = 0

Factor

x^{3} + 2 x^{2} - 16 x - 32 : (x + 2) (x + 4) (x - 4)

(x + 2) (x + 4) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 4 = 0 or x - 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 2, x = - 4, x = 4

3 x \geq 24

Q u a d r a t i c (0.6)

- 4 x < 40

f (x) = 9 x^{2} - 54 x - 19

5^{x} = 8

What are the solutions to the equation roots f(x)=x^3+2x^2-16x-32 ?
The solutions to the equation roots f(x)=x^3+2x^2-16x-32 are x=-2,x=-4,x=4
Find the zeros of roots f(x)=x^3+2x^2-16x-32
The zeros of roots f(x)=x^3+2x^2-16x-32 are x=-2,x=-4,x=4