What are the solutions to the equation roots f(x)=2x^2+16x-9 ?

The solutions to the equation roots f(x)=2x^2+16x-9 are x=(-8+sqrt(82))/2 ,x=-(8+sqrt(82))/2

Find the zeros of roots f(x)=2x^2+16x-9

The zeros of roots f(x)=2x^2+16x-9 are x=(-8+sqrt(82))/2 ,x=-(8+sqrt(82))/2

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roots

f (x) = 2 x^{2} + 16 x - 9

x = \frac{- 8 + 82}{2}, x = - \frac{8 + 82}{2}

Solution steps

2 x^{2} + 16 x - 9

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} + 16 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 (- 9) = 282

x_{1, 2} = \frac{- 16 \pm 2 82}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 16 + 2 82}{2 \cdot 2}, x_{2} = \frac{- 16 - 2 82}{2 \cdot 2}

x = \frac{- 16 + 2 82}{2 \cdot 2} : \frac{- 8 + 82}{2}

x = \frac{- 16 - 2 82}{2 \cdot 2} : - \frac{8 + 82}{2}

The solutions to the quadratic equation are:

x = \frac{- 8 + 82}{2}, x = - \frac{8 + 82}{2}

2.5 km

Q u a d r a t i c (- 7.4)

Q u a d r a t i c (- 3.6)

y = x^{2} + 3 x - 10

32 = x^{5}

What are the solutions to the equation roots f(x)=2x^2+16x-9 ?
The solutions to the equation roots f(x)=2x^2+16x-9 are x=(-8+sqrt(82))/2 ,x=-(8+sqrt(82))/2
Find the zeros of roots f(x)=2x^2+16x-9
The zeros of roots f(x)=2x^2+16x-9 are x=(-8+sqrt(82))/2 ,x=-(8+sqrt(82))/2