What are the solutions to the equation 6x^2+19x+15=0 ?

The solutions to the equation 6x^2+19x+15=0 are x=-3/2 ,x=-5/3

Find the zeros of 6x^2+19x+15=0

The zeros of 6x^2+19x+15=0 are x=-3/2 ,x=-5/3

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6 x^{2} + 19 x + 15 = 0

x = - \frac{3}{2}, x = - \frac{5}{3}

Decimal Notation

x = - 1.5, x = - 1.66666 \dots

Solution steps

6 x^{2} + 19 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 6 \cdot 15}{2 \cdot 6}

1 9^{2} - 4 \cdot 6 \cdot 15 = 1

x_{1, 2} = \frac{- 19 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 19 + 1}{2 \cdot 6}, x_{2} = \frac{- 19 - 1}{2 \cdot 6}

x = \frac{- 19 + 1}{2 \cdot 6} : - \frac{3}{2}

x = \frac{- 19 - 1}{2 \cdot 6} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - \frac{5}{3}

36 x^{2} + 12 x + 1

\frac{∣ 0.5 + 1 ∣}{0.5 + 1} > \frac{1}{0.5 - 1}

- 2 w (w + 9) = 0

\frac{2}{3} (3 x + 6) = 4 x + 3

\frac{4}{2 - x} \geq \frac{3}{1 - x}

What are the solutions to the equation 6x^2+19x+15=0 ?
The solutions to the equation 6x^2+19x+15=0 are x=-3/2 ,x=-5/3
Find the zeros of 6x^2+19x+15=0
The zeros of 6x^2+19x+15=0 are x=-3/2 ,x=-5/3