What are the solutions to the equation solvefor x,x^2+2x=9 ?

The solutions to the equation solvefor x,x^2+2x=9 are x=-1+sqrt(10),x=-1-sqrt(10)

Find the zeros of solvefor x,x^2+2x=9

The zeros of solvefor x,x^2+2x=9 are x=-1+sqrt(10),x=-1-sqrt(10)

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x, x^{2} + 2 x = 9

x = - 1 + 10, x = - 1 - 10

Decimal Notation

x = 2.16227 \dots, x = - 4.16227 \dots

Solution steps

x^{2} + 2 x = 9

Move

9

to the left side

x^{2} + 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 9) = 210

x_{1, 2} = \frac{- 2 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 10}{2 \cdot 1}

x = \frac{- 2 + 2 10}{2 \cdot 1} : - 1 + 10

x = \frac{- 2 - 2 10}{2 \cdot 1} : - 1 - 10

The solutions to the quadratic equation are:

x = - 1 + 10, x = - 1 - 10

1.05 \cdot 1 0^{4}

\frac{( 5 ! )}{( 3 ! )}

\frac{4}{9}

\frac{( 8 x ^{2} - 10 x + 3 )}{( 6 x ^{2} + 3 x - 3 )}

x, 3 x - 19 = 0

What are the solutions to the equation solvefor x,x^2+2x=9 ?
The solutions to the equation solvefor x,x^2+2x=9 are x=-1+sqrt(10),x=-1-sqrt(10)
Find the zeros of solvefor x,x^2+2x=9
The zeros of solvefor x,x^2+2x=9 are x=-1+sqrt(10),x=-1-sqrt(10)