What is the answer to log_{9}(x)+log_{9}(x+2)-1/2 =0 ?

The answer to log_{9}(x)+log_{9}(x+2)-1/2 =0 is x=1

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log_{9}(x)+log_{9}(x+2)-1/2 =0

lo g_{9} (x) + lo g_{9} (x + 2) - \frac{1}{2} = 0

x = 1

Solution steps

lo g_{9} (x) + lo g_{9} (x + 2) - \frac{1}{2} = 0

Apply log rules

x (x + 2) = 3

Solve

x (x + 2) = 3 : x = 1, x = - 3

x = 1, x = - 3

Verify Solutions:

x = 1

True

, x = - 3

False

The solution is

x = 1

lo g_{a} (2) = 1

lo g_{2} (x + 2) = 0

lo g_{4} (4 x - 8) = 3

- lo g_{10} (x) = 2

2 ln (x) = ln (x)

What is the answer to log_{9}(x)+log_{9}(x+2)-1/2 =0 ?
The answer to log_{9}(x)+log_{9}(x+2)-1/2 =0 is x=1
Solve for x: log_{9}(x)+log_{9}(x+2)-1/2 =0
The solution is x=1