What is the answer to log_{3}(3x^2+3x+3)=2 ?

The answer to log_{3}(3x^2+3x+3)=2 is x=1,x=-2

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log_{3}(3x^2+3x+3)=2

lo g_{3} (3 x^{2} + 3 x + 3) = 2

x = 1, x = - 2

Solution steps

lo g_{3} (3 x^{2} + 3 x + 3) = 2

Apply log rules

3 x^{2} + 3 x + 3 = 9

Solve

3 x^{2} + 3 x + 3 = 9 : x = 1, x = - 2

x = 1, x = - 2

lo g_{2} (4 x) = 6

ln (2 x) = 2 x

lo g_{8} (3 x + 5) = 4

ln (y) + 10 y = 140009.3489

7 \cdot ln (\frac{x}{5}) - 1 = 20

What is the answer to log_{3}(3x^2+3x+3)=2 ?
The answer to log_{3}(3x^2+3x+3)=2 is x=1,x=-2
Solve for x: log_{3}(3x^2+3x+3)=2
The solution is x=1,x=-2