What is the answer to 2log_{2}(x)=log^2_{2}(x) ?

The answer to 2log_{2}(x)=log^2_{2}(x) is x=4,x=1

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2log_{2}(x)=log^2_{2}(x)

2 lo g_{2} (x) = lo g_{2}^{2} (x)

x = 4, x = 1

Solution steps

2 lo g_{2} (x) = lo g_{2}^{2} (x)

Rewrite the equation with

lo g_{2} (x) = u

2 u = u^{2}

Solve

2 u = u^{2} : u = 2, u = 0

u = 2, u = 0

Substitute back

u = lo g_{2} (x),

solve for

x

Solve

lo g_{2} (x) = 2 : x = 4

Solve

lo g_{2} (x) = 0 : x = 1

x = 4, x = 1

Verify Solutions:

x = 4

True

, x = 1

True

The solutions are

x = 4, x = 1

2 ln (x) = ln (18) + ln (x - 4)

y, ln (2 y) = x

2 lo g_{2} (x - 4) + lo g_{2} (2) = 3

lo g_{10} (x^{2}) = - 2

ln (1 - x) = \frac{10}{3} x - 4.16

What is the answer to 2log_{2}(x)=log^2_{2}(x) ?
The answer to 2log_{2}(x)=log^2_{2}(x) is x=4,x=1
Solve for x: 2log_{2}(x)=log^2_{2}(x)
The solution is x=4,x=1