What is the answer to log_{5}(3x+1)=-2 ?

The answer to log_{5}(3x+1)=-2 is x=-8/25

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log_{5}(3x+1)=-2

lo g_{5} (3 x + 1) = - 2

x = - \frac{8}{25}

Decimal

x = - 0.32

Solution steps

lo g_{5} (3 x + 1) = - 2

Apply log rules

3 x + 1 = \frac{1}{25}

Solve

3 x + 1 = \frac{1}{25} : x = - \frac{8}{25}

x = - \frac{8}{25}

lo g_{10} (x + 1) + lo g_{10} (2) = lo g_{10} (5 x)

lo g_{10} (3 x) = x - 1

lo g_{x + 1} (x^{2} - 3 x + 1) = 1

ln (x) = ln (3 x + 1) + 1

lo g_{2} (2 - x) = 3

What is the answer to log_{5}(3x+1)=-2 ?
The answer to log_{5}(3x+1)=-2 is x=-8/25
Solve for x: log_{5}(3x+1)=-2
The solution is x=-8/25